Warning: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in…
You need to take a look at the $result variable used to define the loop. More than likely there is a syntax error on the reported line before the $result field, or the value of $result does not exist.
Supplied argument is not a valid stream resource…
This is usually caused when your code is looking for a table or other resource in the database that does not exist.
